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UPSC Prelims 2010 Q116: Science & Technology – Quantitative Aptitude

UPSC Prelims 2010, General Studies Paper I · Science & Technology

A candidate attempted 12 questions and secured full marks in all of them. If he obtained 60% marks in the test and all questions carried equal marks, then what is the total number of questions in the test?
  1. (a) 36
  2. (b) 30
  3. (c) 25
  4. (d) 20

Answer: (d) 20

Explanation

Finding total questions from a percentage and a raw score

A candidate got full marks on 12 questions, which together equal 60% of the total marks.

StepCalculation
Let total questions = NEach question has equal marks
Marks from 12 questionsRepresents 60% of total marks
Equation12/N = 60/100
SolveN = 12 × 100/60 = 20

Why this works:

PointDetail
Equal marks per questionLets us treat question count proportionally to marks
12 questions = 60% of totalDirectly gives N = 20

Answer: (d) 20.

Why each option is right or wrong

Key point

Since 12 fully-correct questions equal 60% of total marks (with equal marks per question), the total number of questions N satisfies 12/N = 60/100, giving N = 20.

Remember

12 fully-correct questions = 60% of total marks → total questions = 20.

Common mistakes

Exam tip

'X questions = Y% of total, equal marks each' → total = X × 100/Y. A simple, frequently tested proportion setup.

Sources

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