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UPSC Prelims 2009 Q99: Science & Technology – Quantitative Aptitude

UPSC Prelims 2009, General Studies Paper I · Science & Technology

There are four persons A, B, C, D; and A has some coins. A gave half of the coins to B and 4 more besides. B gave half of the coins to C and 4 more besides. C gave half of the coins to D and 4 more besides. Both B and D end up with same number of coins. How many coins did A have originally?
  1. (a) 96
  2. (b) 84
  3. (c) 72
  4. (d) 64

Answer: (c) 72

Explanation

A backward-solving coin-sharing puzzle among four persons

Four persons — A, B, C, D — pass along coins following a repeated "half plus 4" rule, with persons B and D ending up with the same number of coins — we need the number of coins person A had originally.

StepWorking forward with A's original coins = x
Person A gives person Bx/2 + 4 coins; A keeps x/2 − 4 coins
Person B gives person C(x/2+4)/2 + 4 = x/4 + 6 coins; B keeps (x/2+4) − (x/4+6) = x/4 − 2 coins
Person C gives person D(x/4+6)/2 + 4 = x/8 + 7 coins; C keeps (x/4+6) − (x/8+7) = x/8 − 1 coins
Person D ends up withx/8 + 7 coins
Setting B's final coins equal to D's final coinsx/4 − 2 = x/8 + 7
SolvingMultiply by 8: 2x − 16 = x + 56 → x = 72 coins

Answer: (c) 72.

Why each option is right or wrong

Key point

Working through each 'half plus 4' transfer step by step and setting B's final coin count equal to D's final coin count gives A's original amount: 72.

Remember

Coin-sharing puzzle (half + 4 rule, B and D end equal): A originally had 72 coins.

Common mistakes

Exam tip

For sequential 'half plus a fixed amount' puzzles, carefully track each person's running total algebraically, then set up the final equality condition precisely as stated.

Sources

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