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UPSC Prelims 2009 Q100: Science & Technology – Quantitative Aptitude

UPSC Prelims 2009, General Studies Paper I · Science & Technology

While adding the first few continuous natural numbers, a candidate missed one of the numbers and wrote the answer as 177. What was the number missed?
  1. (a) 11
  2. (b) 12
  3. (c) 13
  4. (d) 14

Answer: (c) 13

Explanation

Finding the missed number in a natural-number sum

A candidate summed the first few continuous natural numbers but missed one, getting 177 — we need the missed number.

StepReasoning
Try n=19Full sum = 19×20/2 = 190; missed number = 190 − 177 = 13 (valid, since 13 ≤ 19)
Try n=18Full sum = 18×19/2 = 171, which is already LESS than 177 — impossible, since removing a number can only make the total smaller, never larger
Conclusionn=19 is the correct natural-number range, with the missed number being 13

Why n=19 is the right choice:

PointDetail
Full sum (1 to 19)190
Missed number190 − 177 = 13
Validity check13 is indeed within 1 to 19

Answer: (c) 13.

Why each option is right or wrong

Key point

Testing n=19 gives a full sum of 190; since the candidate's total was 177, the missed number is 190 − 177 = 13 — a valid number within the 1-to-19 range.

Remember

Sum of first 19 natural numbers = 190; with 177 given, the missed number is 13.

Common mistakes

Exam tip

For 'missed number in a sum' puzzles, find the full sum n(n+1)/2 that's just slightly ABOVE the given (incomplete) total, then subtract to get the missed number — always verify it falls within 1 to n.

Sources

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