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UPSC Prelims 2024 Q14: Geography – Atmosphere & Climatology

UPSC Prelims 2024, General Studies Paper I · Geography

With reference to “Coriolis force”, which of the following statements is/are correct ? 1. It increases with increase in wind velocity. 2. It is maximum at the poles and is absent at the equator. Select the answer using the code given below :
  1. (a) 1 only
  2. (b) 2 only
  3. (c) Both 1 and 2
  4. (d) Neither 1 nor 2

Answer: (c) Both 1 and 2

Explanation

Coriolis Force — Properties

StatementClaimVerdictWhy
1Coriolis force increases with wind velocityTRUECoriolis force formula: F = 2mΩv sinφ where Ω = Earth's angular velocity, v = wind speed, φ = latitude. Force is directly proportional to velocity (v) - faster winds experience greater Coriolis deflection.
2Coriolis force is maximum at poles, absent at equatorTRUEFrom formula: sinφ factor. At poles (φ = 90°): sin 90° = 1 (maximum). At equator (φ = 0°): sin 0° = 0 (absent/zero). This is why cyclones cannot form at the equator (no Coriolis force to initiate spin).

Coriolis Force Key Properties:

PropertyDetail
DirectionRight in Northern Hemisphere, Left in Southern Hemisphere
CausesDeflection of winds, ocean currents, projectiles
Max latitudePoles (sin 90° = 1)
Min latitudeEquator (sin 0° = 0) - hence no cyclones at equator
Proportional toWind velocity AND latitude
NOT a real forceIt is an apparent force - result of Earth's rotation

Both statements 1 and 2 are correct.

Answer: (c) Both 1 and 2.

Why each option is right or wrong

Key point

Coriolis force = 2mΩv sinφ. Increases with velocity (∝ v). Maximum at poles (sin 90° = 1). Zero at equator (sin 0° = 0). NH = deflects right. SH = deflects left. No cyclones at equator.

Remember

Coriolis force increases with wind velocity and is maximum at poles (sin 90°) but absent at the equator (sin 0°). This is why cyclones cannot form or cross the equator.

Common mistakes

Exam tip

Coriolis force mnemonic: 'VLAT' = Velocity increases it, Latitude determines it (sin φ), Absent at equator, Twin maxima at poles. Formula: F = 2mΩv sinφ. NH = right deflection. SH = left deflection.

Sources

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