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UPSC Prelims 2009 Q106: Science & Technology – Quantitative Aptitude

UPSC Prelims 2009, General Studies Paper I · Science & Technology

In a carrom board game competition, m boys and n girls (m > n > 1) of a school participate in which every student has to play exactly one game with every other student. Out of the total games played, it was found that in 221 games one player was a boy and the other player was a girl. Consider the following statements : 1. The total number of students that participated in the competition is 30. 2. The number of games in which both players were girls is 78. Which of the statements given above is/are correct ?
  1. (a) 1 only
  2. (b) 2 only
  3. (c) Both 1 and 2
  4. (d) Neither 1 nor 2

Answer: (c) Both 1 and 2

Explanation

A boy-girl tournament combinatorics puzzle

With m boys and n girls (m > n > 1), every pair of students plays exactly one game, and 221 games were boy-vs-girl matchups.

StepReasoning
Boy-girl games formulaNumber of boy-vs-girl games = m × n (each boy plays each girl once)
Factor 221221 = 13 × 17, and since m > n, we get m = 17, n = 13
Statement 1: total students = 3017 + 13 = 30 — Correct
Statement 2: girl-vs-girl games = 78Number of girl-girl games = C(13, 2) = 13×12/2 = 78 — Correct

Verifying both statements:

PointDetail
m, n valuesm=17, n=13 (from factoring 221)
Total students17+13 = 30
Girl-girl gamesC(13,2) = 78

Answer: (c) Both 1 and 2.

Why each option is right or wrong

Key point

Factoring 221 = 13 × 17 gives m=17 boys and n=13 girls (since m>n), confirming BOTH the total of 30 students AND the 78 girl-vs-girl games — both statements are correct.

Remember

221 boy-girl games → m=17 boys, n=13 girls → 30 total students, and 78 girl-girl games — both statements correct.

Common mistakes

Exam tip

Mixed-pair game count = m × n (boys × girls). Same-gender game count = C(m,2) or C(n,2). Two distinct combinatorics formulas for this classic puzzle type.

Sources

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