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UPSC Prelims 2008 Q7: Science & Technology – Quantitative Aptitude

UPSC Prelims 2008, General Studies Paper I · Science & Technology

In an examination, 70% of the students passed in the Paper I, and 60% of the students passed in the Paper II. 15% of the students failed in both the papers while 270 students passed in both the papers. What is the total number of students?
  1. (a) 600
  2. (b) 580
  3. (c) 560
  4. (d) 540

Answer: (a) 600

Explanation

Finding total students from overlapping pass/fail percentages

With 70% passing Paper I, 60% passing Paper II, 15% failing both, and 270 students passing both, we need the total number of students.

StepCalculation
Pass at least one paper100% − 15% (fail both) = 85%
Pass both papers (inclusion-exclusion)P(I) + P(II) − P(at least one) = 70 + 60 − 85 = 45%
45% of total = 270 studentsTotal = 270 / 0.45 = 600

Why inclusion-exclusion applies here:

PointDetail
FormulaP(A∩B) = P(A) + P(B) − P(A∪B)
P(A∪B)Equals 100% minus the percentage failing both

Answer: (a) 600.

Why each option is right or wrong

Key point

Using inclusion-exclusion: 45% of students passed both papers (70+60−85, where 85% is 'at least one pass'). Since 45% = 270 students, the total is 270/0.45 = 600.

Remember

70% pass I, 60% pass II, 15% fail both, 270 pass both: total students = 600.

Common mistakes

Exam tip

For overlapping pass/fail percentage problems: use P(A∩B) = P(A)+P(B)−P(A∪B), where P(A∪B) = 100% − (% failing both).

Sources

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