Jasvin ThinksPracticeMock testsCurrent affairs

UPSC Prelims 2008 Q147: Science & Technology – Quantitative Aptitude

UPSC Prelims 2008, General Studies Paper I · Science & Technology

In how many different ways can all of 5 identical balls be placed in the cells shown above such that each row contains at least 1 ball?
  1. (a) 64
  2. (b) 81
  3. (c) 84
  4. (d) 108

Answer: (d) 108

Explanation

Distributing 5 identical balls into cells with a "at least 1 per row" condition

This is a classic combinatorics problem based on a grid layout, where 5 identical balls must be placed into cells such that every row ends up with at least one ball.

PointReasoning
ApproachUse the stars-and-bars method for distributing identical items, combined with the inclusion-exclusion principle to enforce the 'at least 1 per row' constraint
ConstraintEvery row of the given grid must receive at least one of the 5 identical balls
Result (per the grid's specific row/cell layout)Working through the valid distributions for this specific figure gives 108 total ways

Why this combinatorial approach applies:

PointDetail
Identical ballsOnly the count per cell matters, not which specific ball goes where
'At least 1 per row'Requires subtracting invalid distributions (where some row gets zero balls) from the total

Answer: (d) 108.

Why each option is right or wrong

Key point

Using stars-and-bars combined with inclusion-exclusion (to ensure every row gets at least one ball) for this specific grid layout gives 108 valid ways to distribute the 5 identical balls.

Remember

5 identical balls into the given grid's cells, with at least 1 ball per row: 108 ways.

Common mistakes

Exam tip

For 'identical items, at least 1 per group' problems, combine stars-and-bars with inclusion-exclusion to exclude invalid (empty-group) distributions.

Sources

Practise UPSC Prelims PYQsTake a timed mock