Jasvin ThinksPracticeMock testsCurrent affairs

UPSC Prelims 2008 Q10: Science & Technology – Quantitative Aptitude

UPSC Prelims 2008, General Studies Paper I · Science & Technology

March 1, 2008 was Saturday. Which day was it on March 1, 2002?
  1. (a) Thursday
  2. (b) Friday
  3. (c) Saturday
  4. (d) Sunday

Answer: (b) Friday

Explanation

Finding the day of the week six years earlier

Given March 1, 2008 was a Saturday, we need the day of the week for March 1, 2002.

StepReasoning
Count days between the two dates6 years = 6×365 days, plus leap days falling within the span
Leap days within [Mar 1, 2002, Mar 1, 2008)Feb 29, 2004 AND Feb 29, 2008 both fall within this range — 2 leap days
Total days6×365 + 2 = 2190 + 2 = 2192
2192 mod 72192 = 313×7 + 1, so remainder = 1
Interpretation2008's weekday = 2002's weekday + 1 (mod 7)
Solve for 2002Since 2008 is Saturday, 2002's weekday = Saturday − 1 = Friday

Why both leap days matter:

PointDetail
Feb 29, 2004Falls within the span (before Mar 2004)
Feb 29, 2008Falls within the span too (just before the Mar 1, 2008 endpoint)

Answer: (b) Friday.

Why each option is right or wrong

Key point

Between March 1, 2002 and March 1, 2008, TWO leap days (Feb 29, 2004 and Feb 29, 2008) fall within the span, giving a total shift of 1 weekday — so March 1, 2002 was a Friday, one day before Saturday.

Remember

March 1, 2008 was Saturday; accounting for 2 leap days (2004, 2008) in between, March 1, 2002 was a Friday.

Common mistakes

Exam tip

When calculating weekday shifts across multiple years, carefully check EVERY leap day that falls within the exact date range — including one near either endpoint.

Sources

Practise UPSC Prelims PYQsTake a timed mock