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UPSC Prelims 2008 Q1: Science & Technology – Logical Reasoning & Puzzles

UPSC Prelims 2008, General Studies Paper I · Science & Technology

In the series AABABCABCDABCDE... which letter occupies the 100th position?
  1. (a) H
  2. (b) I
  3. (c) J
  4. (d) K

Answer: (b) I

Explanation

Finding the 100th letter in a growing-block series

The series AABABCABCDABCDE... is built from successive blocks: A, AB, ABC, ABCD, ABCDE, ..., where block *n* has *n* letters (A through the *n*th letter).

StepCalculation
Cumulative length after block nn(n+1)/2
After block 1313×14/2 = 91
After block 1414×15/2 = 105
Position 100 falls inBlock 14 (positions 92 to 105), since 91 < 100 ≤ 105
Position within block 14100 − 91 = 9th letter of block 14
Block 14's lettersA, B, C, D, E, F, G, H, I, J, K, L, M, N — the 9th is I

Why the triangular-number formula applies:

PointDetail
Block n lengthn letters (A to the nth letter of the alphabet)
Cumulative totaln(n+1)/2, the triangular number formula

Answer: (b) I.

Why each option is right or wrong

Key point

The series is built from blocks of growing length (A, AB, ABC, ...); using the triangular-number formula n(n+1)/2 to locate block 14, position 100 lands on the 9th letter of that block, which is I.

Remember

Series AABABCABCD...: the 100th position falls on the 9th letter of block 14, which is I.

Common mistakes

Exam tip

For growing-block letter series, use the triangular-number formula n(n+1)/2 to find which block a given position falls into, then count within that block.

Sources

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