UPSC Prelims 2005 Q144: Current Affairs – Tennis Grand Slams
Match items in List - I with List - II and select the correct answer using the codes given below
the lists:
List - I (Lawn Tennis Tournament)
A. French Open 2004
B. Wimbledon 2004
C. US Open 2004
D. Australian Open 2004
List - II (Winner of Women’s Singles)
1. Svetlana Kuznetsova
2. Anastasia Myskina
3. Maria Sharapova
4. Serena Williams
5. Justine Henin Harden
- (a) 5 1 4 2
- (b) 2 3 1 5
- (c) 5 3 1 2
- (d) 2 1 4 5
Answer: (b) 2 3 1 5
Explanation
Women's singles winners of Grand Slams in 2004
| Tournament | Winner |
|---|---|
| A. French Open 2004 | Anastasia Myskina (2) |
| B. Wimbledon 2004 | Maria Sharapova (3) |
| C. US Open 2004 | Svetlana Kuznetsova (1) |
| D. Australian Open 2004 | Justine Henin-Hardenne (5) |
The correct matching is A-2, B-3, C-1, D-5.
Answer: (b) 2 3 1 5.
Why each option is right or wrong
- (a) Incorrect. Henin did not win the French Open in 2004.
- (b) CORRECT. Myskina, Sharapova, Kuznetsova, Henin.
- (c) Incorrect. Henin did not win the French Open in 2004.
- (d) Incorrect. Kuznetsova won the US Open, not Wimbledon.
Key point
2004 women's Grand Slams: Henin (AO), Myskina (FO), Sharapova (Wimbledon), Kuznetsova (US Open).
Remember
Sharapova won Wimbledon in 2004 and Kuznetsova won the US Open.
Common mistakes
- Crediting Serena Williams with Wimbledon 2004.
- Forgetting that Sharapova won at age 17.
- Mixing the Australian winner with the French one.
Exam tip
2004 winners were all first-time Slam champions except Henin.
Sources
- Women's Tennis Association — Grand Slam champions of 2004 (Justine Henin, Anastasia Myskina, Maria Sharapova, Svetlana Kuznetsova)
- Encyclopaedia Britannica — Grand Slam (tennis)