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UPSC Prelims 2004 Q104: Science & Technology – Quantitative Aptitude

UPSC Prelims 2004, General Studies Paper I · Science & Technology

A and B start from the same point and in the same direction at 7 a.m. to walk around a rectangular field 400 m × 300 m. A and B walk at the rate of 3 km/hr and 2.5 km/hr respectively. How many times shall they cross each other if they continue to walk till 1 and 2.30 p.m.?
  1. (a) Not even once
  2. (b) Once
  3. (c) Twice
  4. (d) Thrice

Answer: (c) Twice

Explanation

> Note for students: The stem in the stored copy is garbled ('till 1 and 2.30 p.m.'), but the answer is 'twice' whether the stop time is 1:30 p.m. or 2:30 p.m., so (c) is safe.

A and B walking round a rectangular field

QuantityValue
Perimeter2 x (400 + 300) = 1,400 m = 1.4 km
Relative speed3 - 2.5 = 0.5 km/hr, same direction
Time between meetings1.4 / 0.5 = 2.8 hours
Meetings by 1:30 p.m. (6.5 h) or 2:30 p.m. (7.5 h)At 2.8 h and 5.6 h: twice; the third meeting is at 8.4 h

A gains one full round on B every 2.8 hours, so they meet at 2.8 h and 5.6 h after 7 a.m. and the third meeting would be at 8.4 hours, after the stop time, so they cross twice.

Answer: (c) Twice.

Why each option is right or wrong

Key point

Same direction around a track: A gains one lap on B each time they meet.

Remember

Walkers in the same direction on a loop meet when the faster gains one lap.

Common mistakes

Exam tip

Meeting interval = perimeter / relative speed.

Sources

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