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UPSC Prelims 2002 Q121: Science & Technology – Physics

UPSC Prelims 2002, General Studies Paper I · Science & Technology

A hollow sphere of radius R, a hollow cube of side R and a thin circular plate of radius R, made up of the same material, are all heated to 20 °C above room temperature. When left to cool in the room, which of them will reach the room temperature first?
  1. (a) Circular plate
  2. (b) Cube
  3. (c) Sphere
  4. (d) All of them will reach the room temperature at the same time

Answer: (a) Circular plate

Explanation

Cooling of a hollow sphere, a hollow cube and a thin plate

BodyCooling feature
Thin circular plateThinnest, so the largest surface area for its mass; loses heat fastest
Hollow cubeThicker shell, smaller area per unit mass
Hollow sphereSmallest surface for its volume; loses heat slowest
Same time for allNot true, since the area-to-mass ratio differs

The three bodies are of the same material and are heated to 20 °C above the room temperature. The rate of loss of heat depends on the surface area exposed, and the thin circular plate has the greatest area for its mass. So the circular plate reaches room temperature first. The stored key (c), the sphere, is wrong, because the sphere has the least surface for its volume and cools slowest.

Answer: (a) Circular plate.

Why each option is right or wrong

Key point

Rate of cooling ∝ surface area exposed ÷ heat capacity; thin plates cool faster than compact shapes.

Remember

Largest area for its mass cools first.

Common mistakes

Exam tip

Think of why a spread-out plate cools faster than a compact ball.

Sources

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