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CAPF AC 2023 Q5: General Mental Ability – Quantitative Aptitude

CAPF AC 2023, Paper I (General Ability and Intelligence) · General Mental Ability

A rectangular wall is divided into four squares of equal size where there are two rows each having two squares. The top-left square is coloured with green. If, including green, there are three colours available and each square is coloured using any one of these three colours such that no two adjacent squares get painted with the same colour, then how many colour combinations are possible?
  1. (a) 2
  2. (b) 4
  3. (c) 6
  4. (d) 8

Answer: (c) 6

Explanation

Colouring a two-by-two wall

Given: four equal squares in two rows of two; the top-left is green; three colours including green are available; no two adjacent squares may have the same colour; count the colourings.

How to think: adjacent means sharing a side.

The top-right and bottom-left squares touch the green square, so each can take one of the two other colours.

The bottom-right square touches both of them.

CaseTop-right and bottom-leftChoices for bottom-rightWays
Same colour2 ways (both colour A, or both colour B)Green or the remaining colour: 22 × 2 = 4
Different colours2 ways (A and B, or B and A)Only green is left: 12 × 1 = 2

Total: 4 + 2 = 6.

Answer: (c) 6.

Why each option is right or wrong

Key point

Grid colouring: fix the given square, count choices for its neighbours, then split into cases by whether those neighbours match. Diagonal squares are not adjacent, so they may share a colour.

Remember

Split by whether the two neighbours match: 4 + 2 = 6.

Common mistakes

Exam tip

Educated guess: two squares touch green and each has 2 choices, giving 4 starts. The last square has 1 or 2 choices, so the total lies between 4 and 8. Only 6 is in between.

Sources

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