CAPF AC 2020 Q118: General Mental Ability – Quantitative Aptitude
A wire of length 6 m is stretched such that its radius is reduced by 20%. Which one of the following is the value of increase in its length?
- (a) 50%
- (b) 56.25%
- (c) 62.25%
- (d) 75%
Answer: (b) 56.25%
Explanation
Stretching a wire
Given: a wire of length 6 m is stretched so that its radius is reduced by 20%.
We need the percentage increase in its length.
How to think: stretching does not add or remove metal.
So the volume stays the same.
Volume = area of cross-section × length.
| Step | Working |
|---|---|
| New radius | 80% of old = 0.8 r |
| New area | 0.8 × 0.8 = 0.64 of the old area |
| Volume fixed | Area × length is unchanged |
| New length | 1 ÷ 0.64 = 1.5625 times the old length |
| Increase | 0.5625 = 56.25% |
In metres: the new length is 6 × 1.5625 = 9.375 m.
The increase is 3.375 m, which is 56.25% of 6 m.
The actual length of 6 m does not matter.
The percentage is the same for any wire.
Answer: (b) 56.25%.
Why each option is right or wrong
- (a) Incorrect. 50% does not follow from a 20% cut in radius.
- (b) CORRECT. Area falls to 0.64, so the length rises to 1 ÷ 0.64 = 1.5625, an increase of 56.25%.
- (c) Incorrect. 62.25% is a near miss placed to trap careless working.
- (d) Incorrect. 75% would need a much larger cut in radius.
Key point
Wire stretched: volume constant, so length × radius² is constant. Radius × 0.8 gives area × 0.64 and length × 1.5625: a 56.25% increase.
Remember
Stretched wire: volume is constant; length varies as 1 ÷ radius².
Common mistakes
- Taking the area as falling by 20% instead of 36%.
- Saying the length rises by 36%, the fall in area; the right step is 1 ÷ 0.64.
- Wasting time on the 6 m, which is not needed.
Exam tip
Shortcut: 0.8 is 4/5. Length becomes (5/4)² = 25/16 = 1.5625.
Sources
- NCERT Class IX Mathematics — Surface Areas and Volumes (cylinder)
- NCERT Class X Mathematics — Surface Areas and Volumes (conversion of solids)